Percentage questions for SSC cgl
It is the most crucial chapter in maths. If you understand percentage basic or concept, you can easily manage your time in the exam. Here, we discuss various percentage problems and answer with quick math shortcut tricks methods below in this article. We request all students to read carefully. First, you can attempt your percentage question and answer for ssc cgl with the basic concept and note how much time it will take to finish. Now goes through this article of percentage problems tricks explained in shortcut method. You will see improvement in your time after attempting with the help of these percentage tricks.
IMPORTANT POINT
If you are preparing for any competitive exam, then the maths section is the most important. If you work hard and practice well, you will surely get maximum marks than any other section in the exam. So, the first step is to brush up on your primary concept of every topic of math.
Solve previous year’s question paper with time management. You have to solve maximum questions in less time. Practice and practice are the only way of it. Here in this article, we are providing some percentage tricks for the math percentage chapter. There are six types of examples listed below. You can go through it and do some practice. After practice well, you will see that your timing to solve these percentage questions with tricks improves.
Basically, in a previous article, we provide the profit and loss and work and time tricks
now, we give a percentage chapter of math that is very useful in all exams, and 810 no. of questions are asked from that chapter.
With the help of percentage tricks, we can apply it to various forms like ratio, profit loss, time and distance, graphs, pie charts, etc., these are are the form of a percentage, and if you clear the basic concept, it will be beneficial in many ways.
So, first, what is a percentage.
first what is percentage
DEFINITION
a percentage is a number or ratio expressed as a fraction of 100.
if we have to convert percentage into fraction than it is divide by 100.
Example 1: if we write 45% then its equal to 45/100 or in fraction 9/20 or in decimal 0.45
if we have to convert fraction into percentage we have to multiple with 100.
Example 2 : if we write 3/5 in fraction it is equal to 60%
3/5×100=60.
READ AND LEARN FOLLOWING TABLE as also known as conversion table of percentage. Learn this table it help you a lot to solve many problem.
the following fraction in red colour are MOST IMPORTANT.
Fraction

Percentage

1/1

100%

1/2

50%

1/3

33.33%

1/4

25%

1/5

20%

1/6

16.66%

1/7

14.28%

1/8

12.5%

1/9

11.11%

1/10

10%

1/15

6.66%

1/20

5%

1/25

4%

1/30

3.33%

1/40

2.5%

1/50

2%

1/60

1.66%

1/75

1.33%

1/80

1.25%

1/90

1.11%

1/100

1%

by this conversion table we can change fraction into percentage and percentage into fractionEX: if we have to find 2/5 in %?
then, if we multiply both by 2
then we have 1/5×2 = 2×20%
answer is 2/5 = 40%
so, you only to know basic fraction and percentage that given above.in the inverse
Ex. If we have to find out 1/15 fraction in percentage%?
we get 1/15 = 6.66%
CLICK HERE FOR ALL CHAPTER WISE MATHS SHORTCUT TRICKS
SOME BASIC PERCENTAGE PROBLEMS TRICKS AND SHORTCUTS THAT IS ALWAYS ASKED IN THE EXAMS
PROBLEM ON PERCENTAGE
if there is increase of X% and subsequently X% decrease then there is always loss / decrease in the condition.ex. If rohan salary is increase by 50% and subsequently decrease by 50%. How much percentage loss?ans. By trick — 50×50/100= 25% decrease/lossTYPE 2.
if A is P% more than B. then B is less than by A
with P/(100+P)x100
ex. If radha earning is 25% more than sita. Then sita earning is how many percentage less then by radha?ans. By trick — 25/(100+25)x100=20%
with P/(100P)x100
ex. If golu age is 20% less than gita than gita age is how many percentage more than golu?
ans. By trick — 20/(10020)x100=25%
if there is p% increase in price . how much % decrease his consumption so that his expenditure on it does not change.
formula P/(100+P)x100
ans. 25/(100+25)x100=20%
TYPE 5.
if there is p% decrease in price . how much % increase his consumption so that his expenditure on it does not change.
formula P/(100P)x100
ans. 30/(10030)x100=42.85
TYPE 6.
ans. Difference in % = difference in mark
that is 12%=9marks
so, total mark = 9/12×100= 75
READ MORE
some extent useful
please send arithmetic formula & short tricks.
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